jika f(x) = (2x² - 1)⁸, maka f'(x) =
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Jawaban:
[tex]f'(x) = 8( {2 {x}^{2} - 1})^{7} (4x) \\ = 32x( {2 {x}^{2} - 1})^{7}[/tex]
Jawaban:
32x(2x²-1)⁷
Penjelasan dengan langkah-langkah:
Aturan rantai
f(g(x))'= g(x)' × f'(g(x))
(2x²-1)⁸)'= (2x²-1)' × ((2x²-1)⁸)'
= 4x(8 × (2x²-1)⁷)
= 32x(2x²-1)⁷
[answer.2.content]
